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ACI , O, 12 BC 3 0- 1) C ( 3 + 0 . 4 2 D = ( 1 - 01 42 15A along

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ACI , O, 12 BC 3 0- 1) C ( 3 + 0 . 4 2 D = ( 1 - 01 42 15A along entire z axis in the az direction D 15 A FBC = - 18 ax nN 6 MA FAB = 19.8 a2 nN X FDA = 54 ax NN Ftotal = FDA + FBC = 36ax nN Find the toreve here

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