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ACTIVITY 1 Lesson 2 (Z&T Distribution) Step 5. State the final answer.For numbers 9-10. The average acid content of a certain juice drink is 200

ACTIVITY 1 Lesson 2 (Z&T Distribution)

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Step 5. State the final answer.For numbers 9-10. The average acid content of a certain juice drink is 200 milligrams, and a standard deviation of 12 milligrams. Assume the variable is normally distributed, 9. If a juice drink is selected, what is the probability that the acid content will be greater than 210 miligrams? a. 0.2967 b. 0.2033 C. 0.7967 d.0.2089 10. If a sample of 10 juice drinks is selected, what is the probability that the mean of the sample will be larger than 210 milligrams? a. 0.4959 b. 0.5000 C.0.0041 d.0.42112. Which of the following describes a parameter? a. 40% of Filipinos are in favor of the Federal form of government. b. 30% of the school children in the Philippines like Mathematics C. 45% of 2,000 pupils in a certain school got below 10 on a standardized test. d. 15% of the residents in a certain country are aware of the proper waste disposal. 3. How many possible random samples of size 3 can be drawn from a population of size 12? a. 36 b. 1728 C. 144 d. 220Step 4. Solve the problem Solution: Illustration:a. If a random sample of 20 senior high school students is selected, what is the probability that the average rating is less than 80 %? Step 1. Identify the given information Step 2. Identify what is ask6. Which value of standard deviation defines the best estimate of the population mean? a. 0.20 b. 0.37 c. 0.57 d. 1.3 7. A certain population has a mean of 50 and a standard deviation of 4. A random sample of 15 are drawn from this population. Which describes the sampling distribution of the sample means. a. the sampling distribution of the sample means has a mean of 50, variance of 1.067, and a standard deviation of 1.033. b. the sampling distribution of the sample means has a mean greater than 50, and a standard deviation of 0.033. c. the sampling distribution of the sample means has a mean less than 50, and a standard deviation of 1.033. d. the sampling distribution of the sample means has a mean of 50, variance of 1.067, and a standard deviation of 0.033.\fSolve the following problems: 1. Find the t-value to the left of the mean for

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