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Activity Duration Predecessor Cost to crash by 1 day Max days to crash A 5 - $300 1 B 3 - $100 1 C 4
Activity | Duration | Predecessor | Cost to crash by 1 day | Max days to crash |
A | 5 | - | $300 | 1 |
B | 3 | - | $100 | 1 |
C | 4 | A | $100 | 1 |
D | 3 | A | $200 | 2 |
E | 4 | B | $400 | 3 |
F | 2 | D, E | $500 | 2 |
G | 4 | E | $300 | 3 |
H | 3 | C | $100 | 2 |
- If your task is to crash this project by 2 days, what is the most efficient cost of doing it?(Just input the number with no decimals or dollar signs)
- Suppose that the project duration that you have calculated in question 2 (before crashing) is the expected duration of the project. Its variance of the critical path is 4 days. The principal requires you to complete the project before the day 15. If you finish later, you will incur a fine. What is the probability of receiving a fine?
- Your manager wonders whether or not you should crash the project by 2 days. If you do, the variance of the project duration will remain the same. What is the probability that you will receive a fine? Based on your calculations in Q4 and Q5, would you recommend crashing the project?
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