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After locating a delicious bug, a hungry bat undergoes an acceleration of 4.5 m/s^2 (N 10 degree E) for 0.78 seconds, emerging from the turn

After locating a delicious bug, a hungry bat undergoes an acceleration of 4.5 m/s^2 (N 10 degree E) for 0.78 seconds, emerging from the turn with a velocity of 6.4 m/s (E 35 degrees S). Determine its velocity before it began its turn. Draw a diagram.

Equations:

a^2 = b^2 + c^2 - 2bc cos A

cos A= b^2 + c^2 - a^2/ 2bc

Vav = d/t

Aav=v/t

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