Algorithm A:

long sum = 0;

for (long i = 1; i <= n; i++)

sum = sum + i;

Algorithm B:

sum = 0;

for (long i = 1; i <= n; i++)

{

for (long j = 1; j <= i; j++)

sum = sum + 1;

} // end for

Algorithm C:

sum = n * (n + 1) / 2;

implement the above three algorithms:

There you have the algorithm A, B and C. You will run the three implementations of the algorithms with inputs and do the computation but it does not need to print to the screen the actual sum (for the last value it could exceed the maximum value stored into a long); it should print on the screen the time taken for the running of the algorithm :

1,000,000

1,000,000,000

1,000,000,000,000,000,000

To print the time you should use something like

long startTime = System.currentTimeMillis(); methodA(1000000); long endTime = System.currentTimeMillis(); System.out.println("That method A for 1,000,000 took " + (endTime - startTime) + " milliseconds");