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all of question 4, the code is not that important but would really appreciate if you guys can do it. the denominator says 2theta Exercise

image text in transcribed

all of question 4, the code is not that important but would really appreciate if you guys can do it.

the denominator says 2theta

image text in transcribedimage text in transcribed
Exercise 4 (part c: use R) Let X1, X2, ..., Xn ~ f(x), where /(z) - ed, 120 030. a) (2 points) Find an expression for the maximum likelihood estimator of 0, 0. (by hand) b) (0.5 points) Suppose we obtain the following sample of size n - 4 from this distribution: {2, 3.5, 7, 1.5]. Use these data points to calculate a value of the maximum likelihood estimate of 0. c) (1 point) Using the 4 data points from 4(b), use R to plot the likelihood function as a function of 0. Show your code and plot. . x-axis: 0 from 0 to 10 . y-axis: likelihood, L(0) (or you may plot the log likelihood instead) Hint: Make a sequence for 'r' in R. Then make a function for the likelihood.Exercise 4 (part c: use R) Let X1, X2, ..., Xn ~f(x), where f (x) = e 20, I > 0, 0> 0. a) (2 points) Find an expression for the maximum likelihood estimator of 0, 0. (by hand) b) (0.5 points) Suppose we obtain the following sample of size n = 4 from this distribution: {2, 3.5, 7, 1.5 Use these data points to calculate a value of the maximum likelihood estimate of 0. c) (1 point) Using the 4 data points from 4(b), use R to plot the likelihood function as a function of Show your code and plot. . x-axis: 0 from 0 to 10 . y-axis: likelihood, L(0) (or you may plot the log likelihood instead) Hint: Make a sequence for 'r' in R. Then make a function for the likelihood

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