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all of the methylamine for future meth cooks and not let Jesse and Mike have their shares. Suppose Jesse and Mike decided to sabotage Walter's

all of the methylamine for future meth cooks and not let Jesse and Mike have their shares. Suppose
Jesse and Mike decided to sabotage Walter's cooking operation by ruining the methylamine using the
following gas-phase reaction:
2CH3NH2harr(CH3)2NH+NH3
or, in short:
2AB+C
This reaction converts the methylamine to dimethylamine, using a silica-alumina catalyst. The molat
flow rate into a packed-bed reactor is 23.6mols and the entering pressure is 18atm. Assume there is
no pressure drop or temperature change in the reactor. The reaction rate follows an elementary rate
law in terms of partial pressure.
k1=4.2510-6molatm2*gcatalyst*s and Ke=2.5
(a) Write the mole balance.
(b) Write the rate law in terms of partial pressures.
(c) Set up a stoichiometric table for this reaction.
(d) Write the partial pressures in terms of conversion.
(e) Write the rate law solely in terms of conversion.
(f) What is the equilibrium conversion, xc?
(g) Write out your algorithm in terms of conversion.
(h) How many kilograms of catalyst would Jesse need to load in a PBR to obtain a Who done it?
conversion of 0.9**xe? For x=0.75xe?
(i) How many kilograms of catalyst would be needed to obtain 90% of the equi-
librium conversion in a fluidized bed reactor? If this weight is very, very large, what might you
suggest to reduce the weight? (Ans: W=207.2kg catalyst)
(j) What conversion would be achieved in a 100kg PBR with pressure drop and =0.0098kg-1? A
what catalyst weight does the exit pressure fall below 1.0atm ?
(k) Repeat (j) when pressure drop is accounted for with =610-4kg-1.
While co-teaching CRE with me, PhD student Julia Faeth, created this problem using modifies
data from J. W. Mitchell, et al., Ind. Eng. Chem. Res. 33,181-184(1994).
P5-24 B OEQ (Old Exam Question). Ethyl acetate is an extensively used solvent and can be formed by the vapor
phase esterification of acetic acid and ethanol.
OOII-OOH+CH3CH2OHlongrightarrowCH3-OII-OCH2CH3+H2O
The reaction was etudiad
Acetic Acid
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