All the answers please!

Quiz: PRACTICE ... Question 32 This Quiz: 100 pts possible Submit Quiz Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBQ, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.05 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. Click the icon to view the data table of strontium-90 amounts. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. A. Ho: P1 # #2 OB. HO: H1 = H2 Hy: 19 > H2 H1: H1 # H2 . C. Ho: H1 = 12 OD. HO: H1 SH2 Hy: 17 > #2 H1 : 19 > H12 The test statistic is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. O A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. X More Info City #1 City #2 101 117 86 68 121 100 116 85 101 86 104 107 213 110 137 111 290 137 100 133 284 101 145 209 Print Done