Americans tend to dine out multiple times per week. The number of times a sample of 20 families dined out last week provides the following data. 6 16 3 8 3 1 4 1 3 4 2 2 4 1 1 5 7 3 2 (a) Compute the mean and median. mean 3.35 median 3 (b) Compute the first and third quartiles. first quartile 1.5 third quartile 4.5 (c) Compute the range and interquartile range. range 7 interquartile range 3 (d) Compute the variance and standard deviation. (Round your answers to two decimal places.) variance 4.55526 standard deviation 2.1343 (d) Compute the variance and standard deviation. (Round your answers to two decimal places.) variance standard deviation 4.55526 2.1343 (e) The skewness measure for these data is 0.72. Comment on the shape of this distribution. The skewness measure of 0.72 indicates the data are somewhat skewed to the right Is it the shape you would expect? Why or why not? Yes , most people dine out a relatively few times per week and a few families dine out very frequently, therefore we would expect the data to be positively skewed (f) Compute the lower and upper limits lower limit -3 upper limit 9 Consider the following data. Period Rate of Return (%) 1 -5.0 ST 5 2 -8.0 3 -4.0 4 3.0 5.4 What is the mean growth rate over these five periods? (Round your answer to two decimal places.) 0.98 %