Question
Americans tend to dine out multiple times per week. The number of times a sample of20 familiesdined out last week provides the following data. 72548414144125116632(a)
Americans tend to dine out multiple times per week. The number of times a sample of20 familiesdined out last week provides the following data.
72548414144125116632(a)
Compute the mean and median.
meanmedian
(b)
Compute the first and third quartiles.
first quartilethird quartile
(c)
Compute the range and interquartile range.
rangeinterquartile range
(d)
Compute the variance and standard deviation. (Round your answers to two decimal places.)
variancestandard deviation
(e)
The skewness measure for these data is0.41. Comment on the shape of this distribution.
The skewness measure of 0.41 indicates the data are somewhat
---Select---
skewed to the right
symmetrical
skewed to the left
.
Is it the shape you would expect? Why or why not?
---Select---
Yes
No
, most people dine out a relatively few times per week and a few families dine out very frequently, therefore we would expect the data to be
---Select---
negatively skewed
symmetrical
positively skewed
.
(f)
Compute the lower and upper limits
lower limitupper limit
Do the data contain outliers?
---Select---
No
Some
All
values in the data are less than the lower limit or greater than the upper limit, so there are
---Select---
no
some
many
outliers.
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