Ammonium nitrate (NH4NO3) can decompose according to the following equation: NH4NO3(s) -> N20(g) + 2 H20(g) If 161 g or NH4NO3 (molar mass = 80,06 g/mon decomposes at -25 C and 86.0 kPa, calculate the following: (Use R+0.08206 Latm/ol.) atm mol 1) Pressure of reaction = ) Mole of NH4NO3 reacted = I) Total moles of gases produced = iv) (Total) volume of gases produced = mol L