An agitator of diameter $D$ requires a torque $T$ to rotate at a constant speed $N$ in a liquid of density $$ and

viscosity $.$

If an agitator of $223mm$ diameter rotating at $24re\frac{v}{s}$ in water requires a driving torque of $0\mathrm{.}8Nm.$ Calculate

the corresponding speed $($in rev$/$s$)$ and the torque $($in $Nm)$ required to drive a similar agitator of $693mm$

diameter rotating in air $($Viscosities: air $1\mathrm{.}86{10}^{-5}$ Pa s$,$ water $0\mathrm{.}001$ Pa s$.$ Densities: air $1\mathrm{.}20k\frac{g}{m^3},$ water $1000$

$\{$:$k\frac{g}{m^3}).$

Answer using vector notation with either MATLAB or Python formatting $($e$.$g$.0,0$ or $\left[\begin{array}{cc}0& 0\end{array}\right]).$