An Air Quality instrument logs 0 when standards are not met and 1 when standards are met. The log is saved to file DATA. First, compute the proportion meeting standards as the mean of Air Quality values. Second, at alpha = 0.10 (sensitive, exploratory), test the hypothesis that proportion of times that air quality meets standards is at least 90%. 0 None of the answers are correct. 0 The pvalue of 0.022 indicates that the data provide strong evidence against H0: 11 2 0.90. H0 is rejected at d = 0.10. The status quo has changed. 0 The pvalue of 0.062 indicates that the data provide weak evidence against H0: 11 2 0.90. H0 is rejected at d = 0.10. O The pvalue of 0.966 indicates that the data provide insignificant evidence against H0: 11 2 0.90. H0 is not rejected at c1 = 0.10. The status quo remains unchanged. 0 None of the answers are correct. 0 The pvalue of 0.022 indicates that the data provide strong evidence against H0: at 2 0.90. H0 is rejected at a = 0.10. The status quo has changed. 0 The pvalue of 0.062 indicates that the data provide weak evidence against H0: 11 2 0.90. H0 is rejected at a = 0.10. O The pvalue of 0.966 indicates that the data provide insignificant evidence against H0: 11 2 0.90. H0 is not rejected at G = 0.10. The status quo remains unchanged. 0 The pvalue of 0.006 indicates that the data provide overwhelming evidence against H0: 11 2 0.90. H0 is rejected at (1 = 0.10. Send out an air quality alert.