An Air Quality instrument logs 0 when standards are not met and 1 when standards are met. The log is saved to file DATA. First, compute the proportion meeting standards as the mean of Air Quality values. Second, at alpha = 0.10 (sensitive, exploratory), test the hypothesis that proportion of times that air quality meets standards is at least 90%.

a) The pvalue of 0.062 indicates that the data provide weak evidence against H0: ? ? 0.90. H0 is rejected at ? = 0.10.

b) The pvalue of 0.022 indicates that the data provide strong evidence against H0: ? ? 0.90. H0 is rejected at ? = 0.10. The status quo has changed.

c) The pvalue of 0.006 indicates that the data provide overwhelming evidence against H0: ? ? 0.90. H0 is rejected at ? = 0.10. Send out an air quality alert.

d) The pvalue of 0.966 indicates that the data provide insignificant evidence against H0: ? ? 0.90. H0 is not rejected at ? = 0.10. The status quo remains unchanged.

e) None of the answers are correct

Hint: The sample proportion is the mean of the Air Quality values. Compute the mean to 4 decimal place accuracy. Test H0: ? ? 0.90.