An airplane that heads out in a direction of S20Ehas an air velocity of 450 km/h. Measurements from the ground indicate that the airplane has a direction of S37.5Ewith a ground velocity of 398 km/h. What is the velocity of the wind (magnitude and direction USE cosine law sine law or you can use components method so VPG=VPA+VAG so VAG=sqrt(VAGX^2 + VAGY^2) i know i solved wind velocity is 138.9 km/h I am having difficulty in finding the angle and final direction express angle of air velocity, as quadrant beairng and for the nagle of air velocity/wind velocity, and please explain in depth how to find the direction of the angle of VAG, and how you got that quadrant bearing.

\f