An aluminum can is to be constructed to contain 1900 cm of liquid. Let r and h be the radius of the base and the height of the can respectively. a) Express h in terms of r. (If needed you can enter , as pi.) h = 1900/(pi r^2) b) Express the surface area of the can in terms of r. Surface area = c) Approximate the value of r that will minimize the amount of required material (i.e. the value of r that will minimize the surface area). What is the corresponding value of h? h =