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An AM signal is given by AM (t) = 4[5 +3 cos (27 x 10*r)] cos (a x 10t) volts. Find the total power
An AM signal is given by AM (t) = 4[5 +3 cos (27 x 10*r)] cos (a x 10t) volts. Find the total power dissipated by this AM signal across an equivalent load resistance of 10 0. 3.8
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