An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 30 ft per sec. The heights of the ball in feet is given by the equation s = 2.7t + 30t+6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b. a. After how many seconds is the ball 16 ft above the moon's surface? After 10.78,0.33 seconds the ball will be 16 ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.) b. How many seconds will it take for the ball to hit the moon's surface? It will take 11.32 seconds for the ball to hit the moon's surface. (Round to the nearest hundredth as needed.)