an earth satellite moves in a circular orbit 666km above earths surface with a period of 97.86min. What are (a) the speed and (b) the magnitude of the centripetal acceleration of the satellite?

speed ( v ) = 2 717 T Centripetal acceleration (ac) = where - 8- is the radius of the orbit 7 - is the period of the orbit . First we need to calculate the radius of the orbit in meters . we can do this by adding the altitude of the satellite to the radius of the Earth . Y = 666 km + 637 1 k = 7037 km Now that we have the radius of the orbit. we Can calculate the speed of stetellite . V = 2XTTXY 2X 3. 14 X 7037 T (97. 86 x60 sec ) V = 75 30 . 3 m / sec Finally we can calculate the magnitude of the centripetal acceleration of the satellite . ac = = ( 7530 . 3 ) 2 = 8. 058 m/ sec2 7037 ac = 8.05 8.m / see 2