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An electric car company, Edison Motors, is trying to determine the proper production capacity level for its new electric car. A unit of capacity gives

An electric car company, Edison Motors, is trying to determine the proper production capacity level for its new electric car. A unit of capacity gives us the potential to produce one car per year. It costs $10,000 to build a unit of capacity and the cost is charged equally over the next 5 years, at $2000 per year. It also costs $400 per year to maintain a unit of capacity (whether or not it is used).
Each car sells for $14,000 and incurs a variable production cost of $10,000.
The annual demand for the electric car during each of the next 5 years is believed to be normally distributed with mean 500,000 and standard deviation 100,000. The demands during different years are assumed to be independent.
Profits are discounted at a 7.5% annual interest rate.
The company is working with a 5-year planning horizon. Capacity levels of 300,000,400,000,500,000,600,000, and 700,000 are under consideration. In each year, the company does not produce more than the demand for that year, so no inventory is carried from one year to the next. Perform simulations to analyze this problem.
In this problem, you will build the model as before, but with less given in the starter shell file. You will need to fill in the inputs from the problem statement and the logic to calculate cash flow. The NPV formula is provided for you in cell B36.
Some things to note when you work on this problem:
For all simulations, run at least 1,000 replications.
1.What is the capacity level that maximizes expected (mean) NPV?
2. What is the expected (mean) NPV at the optimal capacity level you determined in Question 1?
Enter your answer in dollars (not millions of dollars, for example).
Use the additional information below for questions 3 and 4:
Due to supply shortages for several key parts used to build the electric car, the variable production cost is uncertain, but expected to be higher over the first 2 years.
The company believes the distribution of variable costs for these 2 years is triangular, with a minimum of $10,000 and maximum of $15,000.
In year 1 the most likely value is $12,000. In year 2 the most likely value is the actual value from year 1. After year 2, variable cost is expected to return to $10,000.
For example, if the year 1 variable cost sampled from the year 1 distribution is $13,706, then the most likely value for the year 2 distribution is $13,706, but the minimum is still $10,000 and the maximum is still $15,000
3. Based on this new information, what is the optimal capacity level?
4. What is the probability that the company loses money at the new optimal capacity level you found in question 3?
Enter the probability as a decimal value rounded to two decimal places. For example, 62.7% would be 0.63.
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