An electric dipole with dipole moment $p=5{10}^{-5}C*m$ sets up an electric field $($in newtons per coulomb$)$

$F(x,y,z)=\frac{kp}{r^5}($:$3xz,3yz,2z^2-x^2-y^2$:$)$

where $r=(x^2+y^2+z^2{)}^{\frac{1}{2}}$ with distance in meters and $k=8\mathrm{.}99{10}^9\frac{N*m^2}{C^2}.$ Calculate the work against $F$ required to move a

particle of charge $q=0\mathrm{.}02C$ from $(1,-5,0)$ to $(2,2,2).$

Note: The force on $q$ is $qF$ newtons.

$($Use decimal notation. Give your answer to one decimal place.$)$

$W=$