An electromagnetic wave with a wavelength of 0.3 m is being propagated in different mediums: air, water, and glass. The refractive index of air, water, and glass are 1, 1.33, and 1.5 respectively. Determine the photon energy, in eV, of the electromagnetic wave in each medium (1 eV = 1.6022 10-19 J). Given: Speed of light in a vacuum (CO) = 2.9979 108 m/s, Planck's constant (h) = 6.626069 10-34 J.s The photon energy of an electromagnetic wave in air, eAir = The photon energy of an electromagnetic wave in water, eWater eV. The photon energy of an electromagnetic wave in glass, eGlass = eV. eV