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An electron is moving at a speed of 4.8 x 10^6 m/s at an angle of 30.0 with respect to a uniform magnetic field of
An electron is moving at a speed of 4.8 x 10^6 m/s at an angle of 30.0 with respect to a uniform magnetic field of 9.2 x 10^-4 T. What is the radius of the resulting helical path? (me=9.11 x 10^-31 kg, qe= 1.6 x 10^-19 C)
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Classical Mechanics
Authors: Herbert Goldstein, Charles P Poole
3rd Edition
0201657023, 9780201657029
