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An existing robot is used in a commercial material laboratory to handle ceramic samples in the high-temperature environment that is part of several test procedures.
An existing robot is used in a commercial material laboratory to handle ceramic samples in the high-temperature environment that is part of several test procedures. Due to changing customer needs, the robot will not meet future service requirements unless it is upgraded at a cost of $1,800 Because of this situation, a new advanced technology robot has been selected for potential replacement of the existing robot. The accompanying estimates have been developed from information provided by some current users of the new robot and data obtained from the manufacturer. The firm's before-tax MARR is 18% per year. Based on this information, should the existing robot be replaced? Assume that a robot will be needed for an indefinite period. Click the icon to view the data for the Defender and the Challenger. 2 Click the icon to view the interest and annuity table for discrete compounding when i = 6% per year Click the icon to view the interest and annuity table for discrete compounding when MARR = 18% per year. The AW value for Defender is $ (Round to the nearest dollar) The AW value for Challenger is $ (Round to the nearest dollar) The defender should be (1) - 1: More Info Current MV Upgrade cost (year 0) Annual expenses Defender $38,900 $1,800 $1,400 in year one, and increasing at the rate of 6% per year thereafter Useful life (years) MV at end of useful life - $1,500 Purchase price Installation cost Annual expenses Useful life (years) MV at end of useful life Challenger $57,000 $5,400 $800 in year one, and increasing by $200 per year thereafter $6,500 Discrete Compounding; i = 6% Single Payment Uniform Series Compound Compound Amount Present Amount Capital Present Factor Worth Factor Sinking Fund Recovery Factor Worth Factor Factor To Find F To Find P Factor To Find F To Find P To Find A Given P Given F To Find A Given A Given A Given F F/P Given P P/F FIA PIA AVF 1.0600 1.0600 1.0000 0.9434 1.0000 1.0600 1.1236 0.8900 2.0600 1.8334 0.4854 0.5454 1.1910 0.8396 3.1836 2.6730 0.3141 0.3741 1.2625 0.7921 4.3746 3.4651 0.2286 0.2886 1.3382 0.7473 5.6371 4.2124 0.1774 0.2374 1.4185 0.7050 6.9753 4.9173 0.1434 0.2034 1.5036 0.6651 8.3938 5.5824 0.1191 0.1791 1.5938 0.6274 9.8975 6.2098 0.1010 0.1610 1.6895 0.5919 11.4913 6.8017 0.0870 0.1470 1.7908 0.5584 13.1808 7.3601 0.0759 0.1359 1.8983 0.5268 14.9716 7.8869 0.0668 0.1268 2.0122 0.4970 16.8699 8.3838 0.0593 0.1193 2.1329 0.4688 18.8821 8.8527 0.0530 0.1130 2.2609 0.4423 21.0151 9.2950 0.0476 0.1076 2.3966 0.4173 23.2760 9.7122 0.0430 0.1030 Single Payment Compound Amount Factor To Find F Given P F/P 1.1800 1.3924 1.6430 1.9388 2.2878 2.6996 3.1855 3.7589 4.4355 5.2338 6.1759 7.2876 8.5994 10.1472 11.9737 Present Worth Factor To Find P Given F P/F 0.8475 0.7182 0.6086 0.5158 0.4371 0.3704 0.3139 0.2660 0.2255 0.1911 0.1619 0.1372 0.1163 0.0985 0.0835 Discrete Compounding; 1= 18% Uniform Series Uniform Gradient Compound Present Sinking Gradient Gradient Capital Amount Worth Present Fund Uniform Factor Factor Recovery Worth Factor Series Factor To Find F Factor To Find P Factor To Find A To Find A Given A Given A To Find P Given F To Find A Glven P FIA PIA Given G Given G AJF A/P P/G ANG 1.0000 0.8475 1.0000 1.1800 0.0000 2.1800 0.0000 1.5656 0.4587 0.6387 0.7182 3.5724 0.4587 2.1743 0.2799 0.4599 1.9354 0.8902 5.2154 2.6901 0.1917 0.3717 3.4828 1.2947 7.1542 3.1272 0.1398 0.3198 5.2312 1.6728 9.4420 3.4976 0.1059 0.2859 7.0834 2.0252 12.1415 3.8115 0.0824 0.2624 8.9670 2.3526 15.3270 4.0776 0.0652 0.2452 10.8292 2.6558 19.0859 4.3030 0.0524 0.2324 12.6329 2.9358 23.5213 4.4941 0.0425 0.2225 14.3525 3.1936 28.7551 4.6560 0.0348 0.2148 15.9716 3.4303 34.9311 4.7932 0.0286 0.2086 17.4811 3.6470 42.2187 4.9095 0.0237 0.2037 18.8765 3.8449 50.8180 5.0081 0.0197 0.1997 20.1576 4.0250 60.9653 5.0916 0.0164 0.1964 21.3269 4.1887 (1) replaced O retained
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