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An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $411,

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An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $411, $469, $405, $231 5 . Compute the range, sample variance, and sample standard deviation cost of repair. The range is $ $2 = dollars2 (Round to the nearest whole number as needed.) s= $ (Round to two decimal places as needed.) 4

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