An investment of $116,000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment eamed 8% Interest, the second 6%, and the third 9%. Total interest from the investments was $9000. The interest from the first investment was 4 times the interest from the second. Find the amounts of the three parts of the investment. Write a linear system of equations. Let x be the first inverstment, y be the second investment, and z be the third investment. Choose the correct answer below. 22.= 16, 000 0 O A. x+y+z=9000 0.08% +0.06y +0.09z = 116,000 0.08x = 0.06y O c. x+y+z= 116,000 0.08x + 0.06y + 0.0929000 0.06x = 4(0.08y) The club invested S at 8%, $ at 6%, and OB. x+y+z116,000 0.08x +0.06y+0.09z = 9000 0.08x = 4(0.06y) OD. x+y+z = 4(0.06y) 0.08x +0.06y +0.092 - 9000 0.08x = 116,000 0.909 orosz5000 at 9%