An object is placed against the center of a thin lens and then moved 72 cm from it along the central axis as the image distance i is measured. The figure gives i versus object distance p out to p; = 48 cm. What is the image distance when p =72 cm? 0 plem) -10 i (cm) =20 Two-lens systems. In the figure, stick figure O (the object) stands on the common central axis of two thin, symmetric lenses, which are mounted in the boxed regions. Lens 1 is mounted within the boxed region closer to O, which is at object distance p1. Lens 2 is mounted within the farther boxed region, at distance d. For this problem, p, = 8.4 cm, lens 1 is diverging, d = 15 cm, and lens 2 is converging. The distance between the lens and either focal point is 5.6 cm for lens 1 and 5.7 cm for lens 2. (You need to provide the proper sign). Find (a) the image distance iz for the image produced by lens 2 (the final image produced by the system) and (b) the overall lateral magnification M for the system, including signs. Also, determine whether the final image is (c) real or virtual, (d) inverted from object O or noninverted, and (e) on the same side of lens 2 as object O or on the opposite side. 90 (a) (b) (c) (d) (e) P1 Lens 1 d Lens2 iz M R/V 1/NI Side +8.4 D.5.6 15 C, 5.7 (a) Number i Units cm (b) Number 0.18 Units This answer has no units (c) real invertedThe figure shows wire section 1 of diameter Dy = 5.50F and wire section 2 of diameter Dz = 3.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 1.50 m shown in section 2 is 13.0 pV. The number of charge carriers per unit volume is 9.00 x 1028 m3. What is the drift speed of the conduction electrons in section 17