An object of mass 550 kg is released from rest 1000 m above the ground and allowed to fall under the influence of gravity. Assuming the force due to air resistance is proportional to the velocity of the object with proportionality constant b = 50 N-sec/m, determine the equation of motion of the object. When will the object strike the ground? [Hint: Here the exponential term is too large to ignore. Use Newton's method to approximate the time t when the object strikes the ground.] Assume that the acceleration due to gravity is 9.81 m / sec Let x(t) represent the distance the object has fallen in t seconds. Determine the equation of motion of the object. x(t) = When will the object hit the ground? The object will hit the ground after seconds. (Round to two decimal places as needed.)A shell of mass 5 kg is shot upward with an initial velocity of 250 misec. The magnitude of the force on the shell due to air resistance is % When will the shell reach its maximum height above the ground? What is the maximum height? Assume the acceleration clue to gravity to be 9.81 m 1" s2. When will the shell reach its maximum height above the ground? The shell will reach maximum height after |:J seconds. (Round to two decimal places as needed.) What is the maximum height? The maximum height is ]:| m. (Round to the nearest whole number as needed.) When the velocity v of an object is very large. the magnitude of the force due to air resistance is proportional to \ 2 with the force acting in opposition to the motion of the object. A shell of mass 4 kg is shot upward from the ground with an initial velocity of 700 mfsec. If the magnitude of the force due to air resistance is {0.1 )V2 when will the shell reach its maximum height above the ground? What is the maximum height? Assume the acceleration due to gravity to be 9.81 m I 52. When will the shell reach its maximum height above the ground? The shell will reach maximum height after I: seconds. {Round to two decimal places as needed.) What is the maximum height? The maximum height is :I m. {Round to the nearest whole number as needed.)