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An oxygen electrode in a basic solution has a voltage of 0.5628V. If PO2=0.1atm, what is the solution pH ? From the emf series, O2+2H2O+4e=4(OH)E=+0.40V
An oxygen electrode in a basic solution has a voltage of 0.5628V. If PO2=0.1atm, what is the solution pH ? From the emf series, O2+2H2O+4e=4(OH)E=+0.40V
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