1. An ultraviolet photon is produced whenever the electron within a Hydrogen atom transitions from a higher energy level down to the ground state, which produces the Lyman lines. Why do these Lyman transitions produce ultraviolet photons, while the Balmer transitions produce visible light photons?

1. Starting from the ground state, there are two paths an electron can take to get to the 6^th energy level with only two transitions. One path is illustrated below in Method 1. In the energy level diagram under Method 2, use the Arrow Tool (under Shapes, found under the Insert tab in Word) to illustrate the other possible path to the 6^th orbital, with just two transitions. In the boxes to the left of the Method 2 diagram, label each transition with the name of the photon used.

a) Method 1:

6

5

4

3

H5

2

Lx

1

b) Method 2:

1. Usethree different photons to bring the electron from the ground state to the 4^th energy level. Use the Arrow Tool to illustrate your transitions with arrows ontheenergy level diagram. In the boxes to the right of the diagram, label each transition with the name of the photon used.

1. How does the energy of a photon emitted when the electron moves from the 3^rd to the 2^nd energy level compare to the energy of a photon absorbed when the electron moves from the 2^nd to the 3^rd energy level? Explain.
6. Determine the amount of energy needed for the following 3 transitions.

• Level 1 to Level 2
• Level 2 to Level 3
• Level 3 to Level 4

1. Explain why these transitions require different energy levels.

Summary/Conclusion (5 points): The identification of absorption or emission lines in the light spectrum of a distant object is the only way we can identify elements in that object. Give a detailed explanation of what is happening within the hydrogen atom to create emission lines. Why do we see absorption lines instead of emission lines when we look at the spectra of stars?