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Analyze the following code: What is the time complexity? int fun(int n) { int count = 0; for (int i = n; i >

  

Analyze the following code: What is the time complexity? int fun(int n) { int count = 0; for (int i = n; i > 0; i /= 2) for (int j=0; j

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The time complexity of the given code is On log n The outer loop runs logn times ... blur-text-image

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