Analyze the following fragment:

double sum $=0$;

double $d=0$;

while $(d10\mathrm{.}0\{$

$d+=0\mathrm{.}1$

sum $+=$ sum $+d$;

$\}$

The program may not stop because of the phenomenon referred to as numerical inaccuracy for operating with floating$-$point numbers.

The program does not compile because sum and $d$ are declared double, but assigned with integer value $0.$

After the loop, sum is $0+0\mathrm{.}1+0\mathrm{.}2+0\mathrm{.}3+$dots$+1\mathrm{.}9$

The program never stops, because $d$ is always $0\mathrm{.}1$ inside the loop.