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Angle at joint C 0= tan 10 45 10 At joint C, Vertical Fy=0 F+Fsin 45 =0 CD BC 2+FCD (sin 45)=0 F =
Angle at joint C 0= tan 10 45 10 At joint C, Vertical Fy=0 F+Fsin 45 =0 CD BC 2+FCD (sin 45)=0 F = 2.707 Kips CD At joint C Horizontal F cos45F CD F CE = F = CE - F = CE AC 0 10.003 2.707(cos 45 ) 8.09 Kips
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Fundamentals of Materials Science and Engineering An Integrated Approach
Authors: David G. Rethwisch
4th Edition
1118214226, 1118061608, 9781118214220, 978-1118061602
