Answe this MATLAB question: The position as a function of time $)$ of a projectile fired with a speed of $v_0$ atAn

an angle a is given by

$x(t)=v_{0}cos*t,y(t)=v_{0}sin*t-\frac{1}{2}g{t}^2$

where $g=9\mathrm{.}81\frac{m}{s^2}.$ The polar coordinates of

the projectile at time $t$ are $(r(t),(t)),$ where

$r(t)=\sqrt[\phantom{2}]{x(t{)}^2+y(t{)}^2}$ and $tan=\frac{y(t)}{x(t)}$

Consider the case where $v_0=160\frac{m}{s}$ and $=60.$ Write a script that determines $r(t)$

and $(t)$ for $t=1,5,9,..\mathrm{.}33s$ and displays the results in a three$-$column table where

the values of $t,r,$ and $$ are displayed in the first, second, and third columns,

respectively.