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Answer and explain MOLECULE #1 (belmontron): Q = 1.602 10-19 & B = 6.6 T diameter = 3.1 cm diameter = 0.2 cm radius =
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MOLECULE #1 (belmontron): Q = 1.602 10-19 & B = 6.6 T diameter = 3.1 cm diameter = 0.2 cm radius = 1.55 cm radius = 0.1 cm 1 cm 2 3 mass = 2.387e-23 kg X mass = 1.54e-24 kg MOLECULE #2 (promodite): Q = 1.602 10-19 & B = 6.6 T 1 cm 2 3 diameter = 0.2 cm diameter = 0.2 cm radius = 0.1 cm radius = 0.1 cm mass = 1.54e-24 g mass= X
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Elements Of Chemical Reaction Engineering
Authors: H. Fogler
6th Edition
013548622X, 978-0135486221
