Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Answer appropriately 3.3 Gauss Law (within a distributed charge) A sphere (r=8cm) holds a charge density of 0.5uC/m3. 0 Calculate the flux through the gaussian

image text in transcribedimage text in transcribed

Answer appropriately

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
3.3 Gauss Law (within a distributed charge) A sphere (r=8cm) holds a charge density of 0.5uC/m3. 0 Calculate the flux through the gaussian surfaces of these spheres: r=2cm, r=4cm & r=8cm and fill Table 3. 0 Calculate the Gaussian surface and electric field at the surface for each of the spheres and fill Table 3. Show your calculations here Gaussian Surface: Gaussian Surface: Gaussian Surface: r=2cm r=4cm R=8cm 4(V . m) Gaussian surface (m2) m Table 3Question 6 4 pts Gaussian surfaces A and B enclose the same positive charge +Q. The area of Gaussian surface A is three times larger than that of Gaussian surface B. The electric flux through Gaussian surface A is O equal to the flux of electric field through Gaussian surface B. O unrelated to the flux of electric field through Gaussian surface B. O nine times larger than the flux of electric field through Gaussian surface B. O three times larger than the flux of electric field through Gaussian surface B. O three times smaller than the flux of electric field through Gaussian surface B.1. Flux for Gaussian Surface. Given O =2.0 x10 *C. Find the flux for a) Gaussian surface S,; b) Gaussian surface S,; c) Gaussian surface S,; and d) Gaussian surface S, -20 SA + Q5) The figure shows electric field lines arising from two small charged particles P and Q. Consider the following two statements: (i) The charge on P is smaller than the charge on Q. (ii) The electrostatic force on P is smaller than the force on Q. Which of the above statements are true? A) Only (i) is true. B) Only (ii) is true. C) Both (i) and (ii) are true. D) Neither (i) nor (ii) is true. 6) Gaussian surfaces A and B enclose the same positive charge +Q. The area of Gaussian surface A is three times larger than that of Gaussian surface B. The electric flux through Gaussian surface A is A) three times smaller than the flux of electric field through Gaussian surface B. B) unrelated to the flux of electric field through Gaussian surface B. C) nine times larger than the flux of electric field through Gaussian surface B. D) three times larger than the flux of electric field through Gaussian surface B. E) equal to the flux of electric field through Gaussian surface B. 7) A solid aluminum cube rests on a wooden table in a region where a uniform external electric field is directed straight upward. What can we say concerning the charge on the top surface of the cube? A) The top surface is neutral. B) The top surface is charged positively. C) The top surface is charged negatively. D) The top surface's charge cannot be determined without further information

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Trigonometry

Authors: Mark Dugopolski

4th Edition

0321915496, 9780321915498

More Books

Students also viewed these Mathematics questions

Question

Context, i.e. the context of the information presented and received

Answered: 1 week ago