answer correctly

17. A better approximation of the wave packet shape can be found by letting A(k) vary according to a Gaussian distribution, this gives a range of wavenumbers that has its largest contribution at the central wavenumber KO and falls to zero for larger or smaller wavenumbers with a characteristic width of Ak. A(k) = Ape -( k-ko) 2 12(Ak ) 2 Obtain and graph the eq. 4.25 from eq. 4.23, with values of k given within the range [-0o, too]. y(x) = / A(k) cos kx dk (4.23) y(x) = AAkv2me (Akx) 12 cos kox (4.25)