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Answer E = 24.0 V r = 1.2 2 27.092 36.0 0 48.0 02 10. If the EMF of the battery above is 24.0 V

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E = 24.0 V r = 1.2 2 27.092 36.0 0 48.0 02 10. If the EMF of the battery above is 24.0 V and its internal resistance r is 1.2 92, what power is dissipated in the 48.0 2 resistor? 6.6 W

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