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Answer each question with work. The answer to each problem is written at the end of each question. . 1When violet light (1:415 nrn) falls
Answer each question with work. The answer to each problem is written at the end of each question.
. 1When violet light (1:415 nrn) falls on a single slit, it creates a diffraction pattern with a central peak 9.20 cm Twide {rst dark fringe to rst dark 'inge) in a screen that is 2.?0111 away. How wide is the single slit? D =.0243 111111 . A \"diamond\" ring= which could be fake is immersed in oil (11:1.43). Light reflected from the diamond-oil interface is totally polarized at an angle of 49.0 degees from the perpendicular. Is this a fake diamond ring? n=2.42 for diamond. n=1.651 fake, most likely glass. ' . A Helium-Neon laser is used to determine me spacing= d= between slits in a diffraction grating. The laser light has a wavelength. 1: 633 nm. The second order bright spot is found at an angle of 43.2 degees. What is the spacing d between slits? d=1.35x10'5m . 1What is the minimum thickness of air between two glass plates if the glass is to appear dark with reected light of wavelength 640 11111? What is the minimum thickness of air if the reection is bright at this wavelength? 1:320nm dark t=160nm bright . 1lliaat is the magnication of a telescope which has an objective lens of focal length 2.50 m and a diameter of 1.00 1n= and an eyepiece of focal length 4.50 cm? 'Nhat is the angular resolution of this telescope for visible light (wavelength = 550 11111}? What is the length of this telescope? M =-55.6_.0m=5.?1x10"l rad, L=2.545m. . 1What is the magnication of a microscope with and object lens of focal length 2.5 cm and diameter 0.500 cm, and a length of 20.0 cm with and eyepiece of focal length 1.50 cm? 'What is the spatial resolution (smallest visible distance) in meters of this microscope? Assime the object being viewed is approximately at the focal point of the objective. M=-123. x=3.35x10'5m . How long is a meter stick moving at a speed 0.9?5c along its direction of motion? L=.222m . What is the mass of a 0.300 kg (1110) baseball moving with a speed of 0.8 50c? 1What is its rest mass energy? 1What is its kinetic energy? 1n=.569kg. nmc3=2axialdl KE = 2.42:;10151 . 1What is the energy released in the following nuclear reaction? 2H +3H J 4He + n 2H m = 3.3734x10'2* kg 3H in = 5.0551x10'\"_kg 4H: m = 5.?039x10j' kg q n 111 = 1.5394310"" kg energy = 3.1?){10'1'} = 19.8MeVStep by Step Solution
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