Answer if you only know 100%. Please explain your answer.
4. Use your obtained data to evaluate, how much time was theoretically spent in uniformly accelerated motion at h? o 1.99 [S] . 0.3728 [s] o 0.7456 [s] o 0.995 [s] o 0.4975 [s] Instrument Measuring Diapason Value of the Smallest Scale Ruler 0 495 mm 1 mm Chronometer 0 99.999 5 0.001 5 MEASUREMENTS No h (mm) H (mm) t(s) tz (s) tz (s) tu (s) ts (s) te (s) 1 267 200 0.374 0.375 0.376 0.376 0.367 0.36 2 148 319 0.897 0.829 0.832 0.842 0.820 0.84 3 167 300 0.736 0.731 0.716 0.718 10.722 0.77: M = 60.15 g 9 m = 8.1 g Intermediate results Direct measurements Height Sh. H = 0.5 Ahs - AHg = 0.3267 mm Ah = AH = 0.3267 mm mm Time (h1) tavg = 0,3728 St = 0.001579 1/3 s At = 0.004060 , = 8 = 0.0005 Ats = 0.0003267 At = 0.004073 Time (h2) tavg = 0.8435 S+ - 0.01120 At = 0.02880 = S. = 10.0005 Ats - 10.0003267S At = 0.02880 5 Time (h3) s tag = 0.7325 S+ = 0.008500 Ats = 0.02185 8 = 0.0005 Ats = 0.0003267 At = 0.02185 s s Indirect measurements Velocity AvexpH = 0.87634 mm/s Avexp. = -5.86128 mm/s h 1: h3: mm/s Avexp = 0.4460 Avexp = -12.2167 mm/s / Free fall acceleration h2: Agn= -16.90779 mm/s? Agh = 15.68873 = mm/s2 / Ag+ = -523.04238 mm/s2 = Main results ht: Vexp = 536.4806866 + 5.92643 Vtheor = 574.765 mm/s mm/s, E = 1.10468 % h2: Vexp = 378.1861292 mm/s Vtheor = 427.9235 mm/s h3 mm/s, E = 2.98489 , % Vexp - 409.5563139 + 12.22483 Vtheor 454.5624 mm/s h2: g= 7659.483 g= + 523.55070 mm/s?, E = 6.835326 % 2/3 h3: g = 7960.87471 mm/s2 4. Use your obtained data to evaluate, how much time was theoretically spent in uniformly accelerated motion at h? o 1.99 [S] . 0.3728 [s] o 0.7456 [s] o 0.995 [s] o 0.4975 [s] Instrument Measuring Diapason Value of the Smallest Scale Ruler 0 495 mm 1 mm Chronometer 0 99.999 5 0.001 5 MEASUREMENTS No h (mm) H (mm) t(s) tz (s) tz (s) tu (s) ts (s) te (s) 1 267 200 0.374 0.375 0.376 0.376 0.367 0.36 2 148 319 0.897 0.829 0.832 0.842 0.820 0.84 3 167 300 0.736 0.731 0.716 0.718 10.722 0.77: M = 60.15 g 9 m = 8.1 g Intermediate results Direct measurements Height Sh. H = 0.5 Ahs - AHg = 0.3267 mm Ah = AH = 0.3267 mm mm Time (h1) tavg = 0,3728 St = 0.001579 1/3 s At = 0.004060 , = 8 = 0.0005 Ats = 0.0003267 At = 0.004073 Time (h2) tavg = 0.8435 S+ - 0.01120 At = 0.02880 = S. = 10.0005 Ats - 10.0003267S At = 0.02880 5 Time (h3) s tag = 0.7325 S+ = 0.008500 Ats = 0.02185 8 = 0.0005 Ats = 0.0003267 At = 0.02185 s s Indirect measurements Velocity AvexpH = 0.87634 mm/s Avexp. = -5.86128 mm/s h 1: h3: mm/s Avexp = 0.4460 Avexp = -12.2167 mm/s / Free fall acceleration h2: Agn= -16.90779 mm/s? Agh = 15.68873 = mm/s2 / Ag+ = -523.04238 mm/s2 = Main results ht: Vexp = 536.4806866 + 5.92643 Vtheor = 574.765 mm/s mm/s, E = 1.10468 % h2: Vexp = 378.1861292 mm/s Vtheor = 427.9235 mm/s h3 mm/s, E = 2.98489 , % Vexp - 409.5563139 + 12.22483 Vtheor 454.5624 mm/s h2: g= 7659.483 g= + 523.55070 mm/s?, E = 6.835326 % 2/3 h3: g = 7960.87471 mm/s2
