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answer please P(x) = CH. x ! - H = rate x time The number of requests for assistance a towing service receives averages 4

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P(x) = CH. x ! - H = rate x time The number of requests for assistance a towing service receives averages 4 per hour. (a) In any given hour, what is the probability they receive exactly five requests for assistance? (enter a number between 0 and 1, 4 decimal places) Answer= The operators of the towing service take a 45-minute break for lunch . Over the lunch break: (b) How many requests for assistance would the towing service expect to receive? Answer= (c) What is the probability they receive no requests for assistance over the lunch break? (enter a number between 0 and 1, 4 decimal places) Answer= (d) What is the probability they will miss at least one request for assistance over the break? (enter a number between 0 and 1, 4 decimal places) Answer=

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