Answer question 2 only, all informations are given.

Question 2 only

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Wi Fi 6 CERTIFIED y Graph : 1.89 6 + 06x + 2.25 0.0015 2840.99 30600 8527-727 20 080 - 0_0045 0. 0075 14204.54 0.0105 19836- 364 6. The column "2x," is your data column. Enter your measurements manually. 0 0135 25568. 132 0.DO)5 0.0050 0.0075 0 010 0.0125 x 7. The remaining columns are calculated columns. Select "New Calculated SPH4UR Lab: Young's Double Slit Experiment Column" from the Data menu and enter an equation to calculate xn. Repeat for the fourth and fifth column. Purpose: To determine the wavelength of the green laser. Create a graph of " versus -and determine the slope. Apparatus: Central Maximum Analysis: Laser L 1 . Based on the slope of the graph, the wavelength of the laser is 5.28 10 7 Slit plate Screen 2x , 2 . Determine the uncertainty of your calculation . TAX 02=5.28X10 3 49-102= 3.43 x108 2x Procedure: 1. Position the slit plate and line up the laser so that it passes through Calculate the percent difference between your experimental value for the 2. Tape a sheet of chart paper to the white board. Mark and label the wavelength of the laser and the known value. locations of antinodal lines 0 to 5 in both directions on the paper. Turn off 4 the laser when you are done. Remove the paper from the board. 532 X100%% 2 0.75 % Mark the location of the nodal lines 1 to 5 in both directions. Measure the spacing, 2x, between symmetric pairs of nodal lines (as shown in the 4. Explain why the slope of the graph represents the wavelength of the laser. diagram) for the first five pairs of nodal lines. The slope of the graph represents the relationship between the normalized Measure the distance L, from the diffraction grating to the screen. Ustance ( xcall ) and (1-s)/d. by examily the equation and Physical Principles of diffraction 5. Create a data table in Graphical Analysis like the one below. it can be determined that the sloe is directly related to the wavelength of the byer 5. How good is your wavelength calculation? Does your value fall within the accepted range ? Why or why not? The accuracy of the wavelength is based on omporily the experimental value withe the accepted range of valves, so my calculations are good. 21 (m) . (m) It is within the accepted range, I think is because the precision and accuracy of the mea for the experimental setup was done welly. 0_006 0.003 0.015 2840- 9 2 0.018 10 009 0-045 8527.7 6. Compare your results with those obtained by other groups. Aside from human error, why can you not expect all groups in your class to obtain the 3 0.030 0-915 0.0075 1 4204.5 same wavelength values? because cosindering that different groups may 4 0.042 0-021 0-0105 /19 9)86 - 36 have different exterimental set up's equipment etc. therefore, variations 5 0.054 0-027 0. 0135 25568 - 182 in the wavelength values obtained by different groups are expected. L= 2m d = 1 76 *10 m factors like measurements techniques, calibration and environmental conditions HAWAI