1. The plane which passes through the point (-1, 0, -6) and perpendicular to the line whose d.rs (6, 20, -1) also passes through the point 1) (1, 1, -26) 2) (0, 0, 0) 3) (2, 1, -32)loom 4) (1, 1, 1) The equation to the plane through the line of intersection of 2x +y+ 3z-2 0, x-y+z+4= 0 s that each plane is at a distance of 2 unit from the origin is 2. 1) x + y + 2z +13 0, x +y + z -3 = 0 2) 2x + y 2z +3 = 0, x 2y - 2z -3 = 0 3) 15x - 12y + 16z +50 = 0, x + 2y + 2z 6 = 0 4) x-y+ 2z 13 = 0, x + y-z-3 = 0 OD TLMNES & LINES The equation of the plane parallel to the plane 2x + 3y + 4z +5 = 0 and passing through the point udents (1,1,1) is 1) 2r + 3y + 4z-9 = 0 2) 2x + 3y + 4z +9 = 0 3) 2r + 3y + 4z +7 = 0 4) 2x + 3y + 4z -7 = 0 The d.r's of the line of intersection of the planes x+y +z-1 0 and 2x + 3y + 4z +7 0 are 1) 1, 2, -3 2) 2, 1, -3 3) 4, 2, -6 plane meets the coordinate axes at A, B, C so that the centroid of the triangle ABC is (1, 2, 4). Then 4) 1, -2, 1 the equation of the plane is 1) x+ 2y + 4z = 12 %3D 2) 4x + 2y + z = 12 3)x+ 2y + 4z = 3 4) 4x + 2y + z = 3