Answer the following two questions: In the Ke determination experiment for the equilibrium reaction shown below: CH3COOH+CH+OHHCHCHOClH7+H2O the [CH2COOH] at any time is determined by NaOH titration and is given by the equation below: [CH2COOH]=mL(mLNootmLtoaccountforHLSO)/1000Mrinat 1. In titration 1 of the initial reaction mixture (before H2SO4 is added), 17.5mL of 0.500MNaOH is required to titrate a 1.00 mL sample from a mixture of 10.00mL of CH3COOH(d=1.09g/mL) and 10.00mL of C3H7OH(d=0.80g/mL). Show the calculation of the initial (CH3COOH) and (C3H2OH) by using the volume and density data. 2. In titration 2 of the initial reaction mixture (after H2SO4 is added) 18.0mL of 0.500MNaOH is required to titrate a 1.00mL sample from the mixture and after the mixture has come to equilibrium, 10.8mL of 0.500MNaOH is required to titrate a 1.00 mL sample from the mixture. Show the cakculation of the equilibrium (CH2COOH) using the tittation data, Using this [CH3COOH], show the calculation of the equilibrium [C3H7OH]1{CH3COOC3H3] and (H2O] and using these data, show the cilculation of the Kc for the above reaction