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Answer the Questions(Multiple Choice ): Question 31 Given the following code for two service classes: public abstract class A { public A(){} public A(String x)

Answer the Questions(Multiple Choice):

Question 31

Given the following code for two service classes: public abstract class A { public A(){} public A(String x) { System.out.println(x + " Overloaded constructor for class A called "); } } public class B extends A { public B() { super("Hello"); } public B(String i) { super(i); } } And given the following code for the application class: public class App { public static void main(String[] args) { B b = new B(); System.out.println("Hello Again "); } } What would the output be when the application class is executed? 
a.

Nothing is output

b.

Hello Overloaded constructor for class A called Hello Again

c.

Hello Again

d.

Overloaded constructor for class A called Hello Again

2.5 points

Question 32

Java, multiple inheritance is implemented with the keyword implements using the concept of

a.

An abstract class

b.

One direct superclass only

c.

An interface

d.

Multiple inheritance is not supported in Java

2.5 points

Question 33

A non abstract subclass extending an abstract superclass must provide the implementation for all direct abstract superclass abstract methods.

True

False

2.5 points

Question 34

For Question 34 consider the following three classes: public class A { private int number; protected String name; public double price; public A() { System.out.println( "A() called"); } private void foo1() { System.out.println( "A version of foo1() called"); } protected int foo2() { System.out.println( "A version of foo2() called"); return number; } public String foo3() { System.out.println( "A version of foo3() called"); return "Hi"; } } public class B extends A { private char service; public B() { super(); System.out.println( "B() called" ); } public void foo1() { System.out.println( "B version of foo1() called"); } protected int foo2() { int n = super.foo2(); System.out.println( "B version of foo2() called"); return ( n + 5 ); } public String foo3() { String temp = super.foo3(); System.out.println( "B version of foo3() called"); return ( temp + " foo3"); } } public class C extends B { public C() { super(); System.out.println( "C() called"); } public void foo1() { System.out.println( "C version of foo1() called"); } } What is the output of the following code sequence: B b2 = new B(); b2.foo1(); 
a.

A() called B() called A version of foo1() called

b.

A() called B() called A version of foo1() called B version of foo1() called

c.

A() called B() called B version of foo1() called

d.

A() called B() called B version of foo1() called A version of foo1() called

2.5 points

Question 35

For Question 35 consider the following three classes: public class A { private int number; protected String name; public double price; public A() { System.out.println( "A() called"); } private void foo1() { System.out.println( "A version of foo1() called"); } protected int foo2() { System.out.println( "A version of foo2() called"); return number; } public String foo3() { System.out.println( "A version of foo3() called"); return "Hi"; } } public class B extends A { private char service; public B() { super(); System.out.println( "B() called" ); } public void foo1() { System.out.println( "B version of foo1() called"); } protected int foo2() { int n = super.foo2(); System.out.println( "B version of foo2() called"); return ( n + 5 ); } public String foo3() { String temp = super.foo3(); System.out.println( "B version of foo3() called"); return ( temp + " foo3"); } } public class C extends B { public C() { super(); System.out.println( "C() called"); } public void foo1() { System.out.println( "C version of foo1() called"); } }

What is the output of the following code sequence: B b3 = new B(); int n = b3.foo2();

a.

A() called B() called A version of foo2() called B version of foo2() called

b.

A() called B() called A version of foo2() called B version of foo2() called 5

c.

A() called B() called B version of foo2() called 5

d.

B() called A() called B version of foo2() called

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