answers are all in the pictures but I have to submit the work on an excel instead of sending it from my iPad notes that I do with a apple pen Just need someone to copy all the answers and type them in to the questions because I'm lazy ) Pictures are in order of questions Question 1 2 The closing price of Schnur Sporting Goods, Inc , common stock is uniformly distributed between $20 and $30 per share What is the probability that the stock price will be a More than $27 b Less than or equal to $24 Question 2 4 According to an insurance survey, a family of four spends between $400 and $3,800 per year on all types of insurance Suppose the money spent is uniformly distributed between these amounts a What is the mean amount spent on insurance b What is the standard deviation of the amount spent c If we select a family at random, what is the probability they spend less than $2000 per year on insurance per year d What is the probability a family spends more than $3000 per year Question 3 2 A recent article in the CollingwoodSun Timesreported that the mean labour cost to repair a heat pump is $90 with a standard deviation of $22 Dawson's Heating Repairs and Services completed repairs on two heat pumps this morning The labour cost for the first was $75, and it was $100 for the second Computez values for each For $75 z For $100 z Question 4 5 A normal population has a mean of 20 0 and a standard deviation of 4 0 (Refer to a Z Score table) a Compute thez value associated with 25 0 b What proportion of the population is between 20 0 and 25 0 c What proportion of the population is less than 18 0 Question 5 1 A college decided to survey its students to see how they felt about using a computer in all classes, and how much extra tuition they would be willing to pay for the service The college made a list of all of the classes registered in the semester and then randomly selected 25 classes All students in the selected 25 classes were surveyed The situation is classified as sampling Identify whether this is situation is classified as (highlight or type selection) A Stratified Random Sampling B Systematic Random Sampling C Cluster Sampling Question 6 4 A normal population has a mean of 60 and a standard deviation of 12 You select a random sample of 9 (Refer to a Z Score table) Compute the probability that the sample mean is a Greater than 63 b Less than 56 c Between 56 and 63 Question 7 2 Givenp 0 45 andn 200, compute the standard error of the proportion Question 8 2 A sample of 81 observations is taken from a normal population with a standard deviation of 5 The sample mean is 40 Determine the 95 confidence interval for the population mean Question 9 5 A sample of 10 observations is selected from a normal population for which the population standard deviation is known to be 5 The sample mean is 20 a Determine the standard error of the mean b Determine the 95 confidence interval for the population mean c Explain why we can use the formula used above to determine the 95 confidence interval, even though the sample size is less than 30 Question 10 5 A sample of 40 observations is selected from a normal population where the population standard deviation is 25 The sample mean is 75 a Determine the standard error of the mean b Determine the 90 confidence interval for the population mean c If you wanted a wider interval, would you increase or decrease the confidence level This is a uniform distribution with or 400 6 3800 Since we know that Probability density function of a uniform distribution is f(x) B a This implies that Cummulative density function of a uniform distribution is FO a)Since we also know that Mean of a uniform distribution is the average of its interval i e Mean 106 0 3800 0 Mean 2 Mean 2100 0 fSolution Given that mean x bar 75, standard deviation o 25, n 40 a standard error of the mean is 3 953 standard error of the mean standard deviation sqit(n) 25 sqrt(40) 3 9528 3 953 (rounded) b The 90 confidence interval for the population mean is between 68 478 and 81 522 for 90 confidence interval, Z 1 65 The 90 confidence interval for the population mean is x bar Z o sqrt(n) 75 1 65 25 sqrt(40) (68 478 81 522) (rounded) C If we increase the confidence level , we get a wider intervalIn stratied sampling, the sampling is done on elements within each stratum In stratified sampling, a random sample is drawn from each of the strata, whereas in cluster sampling onlyr the selected clusters are sampled The main difference between cluster sampling and stratified sampling is that in cluster sampling the cluster is treated as the sampling unit so sampling is done on a population of clusters (at least in the first stage In stratified sampling, the sampling is done on elements within each stratum Here 25 classes are selected as clusters and all the students in the class are surveyed Hence it is cluster sampling The situation is classified as Cluster sampling

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answers are all in the pictures but I have to submit the work on an excel instead of sending it from my iPad notes that

answers are all in the pictures but I have to submit the work on an excel instead of sending it from my iPad notes that I do with a apple pen

Just need someone to copy all the answers and type them in to the questions because I'm lazy:) Pictures are in order of questions

Question 1

The closing price of Schnur Sporting Goods, Inc., common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be:

a. More than $27?

b. Less than or equal to $24?

Question 2

According to an insurance survey, a family of four spends between $400 and $3,800 per year on all types of insurance. Suppose the money spent is uniformly distributed between these amounts.

a.What is the mean amount spent on insurance?

b.What is the standard deviation of the amount spent?

c.If we select a family at random, what is the probability they spend less than $2000 per year on insurance per year?

d.What is the probability a family spends more than $3000 per year?

Question 3

A recent article in the CollingwoodSun Timesreported that the mean labour cost to repair a heat pump is $90 with a standard deviation of $22. Dawson's Heating Repairs and Services completed repairs on two heat pumps this morning. The labour cost for the first was $75, and it was $100 for the second.

Computez-values for each.

For $75:z=

For $100:z=

Question 4	/5

A normal population has a mean of 20.0 and a standard deviation of 4.0.
(Refer to a Z-Score table)

a.Compute thez-value associated with 25.0.


b.What proportion of the population is between 20.0 and 25.0?


c.What proportion of the population is less than 18.0?

Question 5

A college decided to survey its students to see how they felt about using a computer in all classes, and how much extra tuition they would be willing to pay for the service.

The college made a list of all of the classes registered in the semester and then randomly selected 25 classes. All students in the selected 25 classes were surveyed.

The situation is classified as_______ sampling.

Identify whether this is situation is classified as: (highlight or type selection)

A. Stratified Random Sampling

B. Systematic Random Sampling

C. Cluster Sampling

Question 6	/4

A normal population has a mean of 60 and a standard deviation of 12. You select a random sample of 9.
(Refer to a Z-Score table)

Compute the probability that the sample mean is:

a.Greater than 63.


b.Less than 56.


c.Between 56 and 63.

Question 7	/2

Givenp= 0.45 andn= 200, compute the standard error of the proportion.

Question 8	/2

A sample of 81 observations is taken from a normal population with a standard deviation of 5. The sample mean is 40.
Determine the 95% confidence interval for the population mean.

Question 9

A sample of 10 observations is selected from a normal population for which the population standard deviation is known to be 5. The sample mean is 20.

a.Determine the standard error of the mean.

b.Determine the 95% confidence interval for the population mean.

c.Explain why we can use the formula used above to determine the 95% confidence interval, even though the sample size is less than 30.

Question 10	/5

A sample of 40 observations is selected from a normal population where the population standard deviation is 25. The sample mean is 75.

a.Determine the standard error of the mean.

b.Determine the 90% confidence interval for the population mean.

c.If you wanted a wider interval, would you increase or decrease the confidence level?

This is a uniform distribution with or = 400 6 = 3800 Since we know that Probability density function of a uniform distribution is f(x) = B-a This implies that Cummulative density function of a uniform distribution is FO = a)Since we also know that Mean of a uniform distribution is the average of its interval i.e. Mean = 106.0 + 3800.0 Mean = 2 Mean = 2100.0\fSolution: Given that mean x-bar = 75, standard deviation o = 25, n = 40 a. => standard error of the mean is 3.953 =>standard error of the mean = standard deviation sqit(n) = 25/sqrt(40) =3.9528 = 3.953 (rounded) b. => The 90% confidence interval for the population mean is between 68.478 and 81.522 =>for 90% confidence interval, Z = 1.65 =>The 90% confidence interval for the population mean is => x-bar +/- Z*o/sqrt(n) =>75 +/- 1.65*25/sqrt(40) => (68.478 . 81.522) (rounded) C. =>If we increase the confidence level , we get a wider intervalIn stratied sampling, the sampling is done on elements within each stratum. In stratified sampling, a random sample is drawn from each of the strata, whereas in cluster sampling onlyr the selected clusters are sampled. The main difference between cluster sampling and stratified sampling is that in cluster sampling the cluster is treated as the sampling unit so sampling is done on a population of clusters (at least in the first stage]. In stratified sampling, the sampling is done on elements within each stratum. Here 25 classes are selected as clusters and all the students in the class are surveyed Hence it is cluster sampling. The situation is classified as Cluster sampling.