Answery HE P = 545 mph- velocity of plane 0= 145' Q = R 45 mnph = velocit of wing Let P = Velocity of plane = 545 mph as shown in the diagrom Let Q = wind velocity @us south of East = 45 mph as shown in doagrom. . . The angle between p and R = ( 180 - 35 ) = 145 The resultant velocity vector R has a magnitude according to the formula R = P 2+ 2 PQ cos 195 + 02 . . R = (545 ) 2 + 2 x 545x Cos 1450 + 45% R = 508. 79 mmph Let o be the angle made by the Resultunt Rwith Tund = 9 sing 45. Sin145" = 0. 0507 P + Broso 545 + 45. (05/ 45' . . 0 = tun (0. 0507 ) = 2.90 . . The Resultant velocity of the plane will be 508. 79 mph (@ja. 9 south of west.Part B The plane travels 5:45 mph (If on wind ! plane fly due west the whole time - wind 45 mik and 45 degrees south of east Winds velocity of 4s meh 2 .Peraltatelegram ? V - 545 - $ 1 80 1480 My = 0 - 45 2 12 SF 54 mih - velocity of planet RF resultant Velocity vector why wind velocity as ure south of east ( J 2 6 3 2 5 6 , 1 9 + 1 9 1 1 1 6 3 2 2 6 4 2 6 7 1 8 2 Direction . -31, 82 tan ( 1) 2 5 13 18 Jan (0 0 620 1 4 3 5 5 0 Direction + 3 . $5 0