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Anything to help me understand works well! Thank you. QUESTION 11 A university dean is interested in determining the proportion of students who receive some

Anything to help me understand works well! Thank you.

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QUESTION 11 A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than examine the records for all students, the dean randomly selects 200 students and finds that 118 of them are receiving financial aid. Use a 98% confidence interval to estimate the true proportion of students on financial aid. What is the upper limit of this confidence interval? Answer to 2 decimal places. QUESTION 12 Researchers fed cockroaches a sugar solution. Ten hours later, they dissected the cockroaches and measured the amount of sugar in various tissues. Here are the amounts (in micrograms) of d-glucose in the hindguts of 5 cockroaches: 55.95 68.24 52.73 21.50 23.78 From previous work, the researchers expected the population of responses to be Normal. The insects are a random sample from a cockroach population grown in the laboratory. A 95% confidence interval for the mean amount of d-glucose in cockroach hindguts under these conditions is 28.18 to 60.70. 18.69 to 70.19. 31.57 to 57.31. 24.67 to 64.21. QUESTION 13 A random sample of 900 13- to 17-year-olds found that 411 had responded better to a new drug therapy for autism. Let p be the proportion of all teens in this age range who respond better. A 95% confidence interval for p is 0.46 + 0.017. 0.46 + 0.027. 0.46 + 0.033. 0.46 + 0.248. QUESTION 14 A national polling agency conducted a poll in which an SRS of Americans that are registered to vote were contacted regarding whether additional taxes should be imposed on gasoline to encourage individuals to purchase more fuel-efficient automobiles. The agency obtained answers from 1000 Americans and found that 483 would vote for the proposed taxes. Let p represent the proportion of registered voters that would vote for the proposed taxes. How large a sample n would you need to estimate : with margin of error 1% with 95% confidence? n = 1 n = 1500 n = 4800 n = 9593

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