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Apply Demorgan's to: (AB)(C+D) Options a) (A+B) +C+D b) (AB)+C+D c) A+B+C + D d) AB+C + D If you apply DeMorgan's theorem to the
Apply Demorgan's to: (AB)(C+D) Options a) (A+B) +C+D b) (AB)+C+D c) A+B+C + D d) AB+C + D If you apply DeMorgan's theorem to the expression above, you get: Option a) Option b) Option c) Option d)
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