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Apply the final value theorem to find x[]: x[n] =7(1/3) u[n]-6(1/2) u[n] x[n] = 7 (1/3) n u [n] 60/2) n u [n]

Apply the final value theorem to find x[]:

x[n] =7(1/3)" u[n]-6(1/2)" u[n]

x[n] = 7 (1/3) n u [n] 60/2) n u [n]

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